x^2-6x^2-8x+48=0

Solution for x^2-6x^2-8x+48=0 equation:

x^2-6x^2-8x+48=0

We add all the numbers together, and all the variables

-5x^2-8x+48=0

a = -5; b = -8; c = +48;
Δ = b2-4ac
Δ = -82-4·(-5)·48
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-32}{2*-5}=\frac{-24}{-10}
=2+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+32}{2*-5}=\frac{40}{-10}
=-4
$